快速乘+快速幂

计算 aba^b % p

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
int t;
ll a, b, p;
ll fast_mul(ll a, ll b, ll p)
{
    ll res = 0;
    while (b)
    {
        if (b & 1) res = (res + a) % p;
        a = a * 2 % p;
        b >>= 1;
    }
    return res;
}
ll fast_pow(ll a, ll b, ll p)
{
    ll res = 1;
    while (b)
    {
        if (b & 1) res = fast_mul(res, a, p);
        a = fast_mul(a, a, p);
        b >>= 1;
    }
    return res;
}
int main()
{
    cin >> t;
    while (t--)
    {
        scanf("%lld%lld%lld", &a, &b, &p);
        printf("%lld\n", fast_pow(a, b, p));
    }

    return 0;
}